当(i,j)=1时,对于任何正整数n,((i^2-j)n-i,(j^2-i)n+j)=1几乎是正确的,仅有少数反例.- Table[CoprimeQ[(i^2 - j) n - i, (j^2 - i) n + j] || !
- CoprimeQ[i, j ], {i, Range[5]}, {j, Range[25]}, {n, Range[5]}]
复制代码 输出的第一屏甚至全是True
这一共检验了5^4=625组数,只有下面几个反例:
{{2, 3, 2}, {2, 11, 3}, {3, 8, 3}, {3, 17, 2}, {3, 19, 1}, {4, 15,
4}, {5, 2, 2}, {5, 24, 5}} |