悠闲数学娱乐论坛(第2版)'s Archiver

青青子衿 发表于 2019-3-18 20:01

几个反正切函数复合三角函数的定积分

\begin{align*}
\int_0^{\frac{\pi}{2}}\arctan\left(\cos^2x\right)\mathrm{d}x\,\,&\dot{=}\,\,\int_0^{\frac{\pi}{2}}\arctan\left(\sin^2x\right)\mathrm{d}x=\frac{\pi}{2}\arctan\sqrt{\frac{\sqrt{2}-1}{2}}\\
\int_0^{\frac{\pi}{2}}\arctan\left(\sec^2x\right)\mathrm{d}x\,\,&\dot{=}\,\,\int_0^{\frac{\pi}{2}}\arctan\left(\csc^2x\right)\mathrm{d}x=\frac{\pi^2}{4}-\frac{\pi}{2}\arctan\sqrt{\frac{\sqrt{2}-1}{2}}\\
\int_0^{\frac{\pi}{2}}\arctan\left(\tan^2x\right)\mathrm{d}x\,\,&\dot{=}\,\,\int_0^{\frac{\pi}{2}}\arctan\left(\cot^2x\right)\mathrm{d}x=\frac{\pi^2}{8}\\
\end{align*}

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